I was working on some scripts and the changes that I was making in the scripts was very dynamic, which I did want to keep backing up in the version control system. But for the peace of my mind, I wanted to keep a copy of the scripts, whenever it was in working state.
Since I had multiple files, so it would make more sense to have a script that could copy all the files in the current directory to “old” directory without over-writing the existing files. So, I wrote a script that would postfix the files with a number. With this approach, finally what I had was the following:
#!/bin/bash -
#===============================================================================
#
# FILE: backup.sh
#
# USAGE: ./backup.sh
#
# DESCRIPTION: Backup all the current files.
#
# OPTIONS: ---
# REQUIREMENTS: ---
# BUGS: ---
# NOTES: ---
# AUTHOR: Amit Agarwal (aka), amit.agarwal@roamware.com
# COMPANY:
# CREATED: 08/19/2011 02:43:32 PM IST
# REVISION: ---
#===============================================================================
count=$(cat old/count)
if [[ ! -f old/count ]]
then
count=$(ls -1 old |sed 's/.*\.//'|grep -vi "[a-z]"|sort|tail -1)
fi
((count++))
echo $count >old/count
[[ ! -d old ]] && mkdir old
for i in *
do
[[ -f $i ]] && cp $i old/${i%%.*}.$count
done
echo "Backed up to $count"
